我用codewarrior3.1新建了个工程，在start12.c中有这样的定义
#ifdef _HCS12_SERIALMON
/* for Monitor based software remap the RAM & EEPROM to adhere
to EB386. Edit RAM and EEPROM sections in PRM file to match these. */
___INITRG = 0x00; /* lock registers block to 0x0000 */
___INITRM = 0x39; /* lock Ram to end at 0x3FFF */
___INITEE = 0x09; /* lock EEPROM block to end at 0x0fff */
#endif
而在Simulator_linker.prm文件中出示化RAM是
RAM = READ_WRITE 0x0400 TO 0x1FFF;
在start12.c中定义的RAM结束地址不是0x3FFF么？为什么现在是0x0400 TO 0x1FFF？
而start12.c中初始化“lock EEPROM block to end at 0x0fff ”，这个不是和RAM冲突了么？
在数据手册上说INITRM “This register initializes the position of the internal RAM within the on-chip system memory map.”是对RAM11到RAM15可以进行操作，那么其RAM00到RAM10之怎么操作的呢？
请帮忙解答谢谢了先！
[此贴子已经被作者于2007-3-11 2:05:25编辑过] | 
