编程思维挑战！！！ “按下P1^4，LED闪烁时间加快，按下时间越长，闪烁频率越快。
释放开关，频率固定停在当前值闪烁。这才是编程思维挑战“ 首先声明：对于这里的多数人，这当然不是什么编程思维挑战，只不过有人一定要这么说，为了说明这个论坛水平，我这个中低手做了这么一段C代码在visual c++ 的演示，供辉阳的心等初学者参考。我相信有更多的人能做出比这更好的代码。因此，敬请某些人不必再怀疑本论坛众人的智商。
class CLEDTestDlg : public CDialog
{
struct LEDStatus
{
int frequency;
int counter;
bool status;
}
m_LEDStatus;
enum Keyboard
{
NOKEY,
LEFTKEY,
RIGHTKEY
} KEYBOARD; struct KeyStatus
{
Keyboard key;
Keyboard pressedKey;
int keyState;
int keyTimer;
bool keyEventHandled;
}
m_KeyStatus; CStatic LED1; //模仿ＬＥＤ 闪烁。 **********************************************************************
BOOL CLEDTestDlg::OnInitDialog()
{
CDialog::OnInitDialog();
this->SetTimer(1, 20, NULL); //用定时器模仿定时中断。
m_LEDStatus.frequency = 50; //1 second;
m_LEDStatus.counter = 0;
m_KeyStatus.key = NOKEY;
m_KeyStatus.pressedKey = NOKEY;
m_KeyStatus.keyState = 0;
return TRUE;
} void CLEDTestDlg::OnTimer(UINT_PTR nIDEvent) //定时中断
{
BlinkLED();
DetectKeyPress();
} void CLEDTestDlg::BlinkLED()
{
if (++m_LEDStatus.counter >= m_LEDStatus.frequency) {
m_LEDStatus.counter = 0;
LED1.SetWindowText(m_LEDStatus.status ? " " : "*"); //Led 闪烁。
m_LEDStatus.status = !m_LEDStatus.status;
} if (m_KeyStatus.key != NOKEY && !m_KeyStatus.keyEventHandled) {
m_KeyStatus.keyEventHandled = true;
if (m_KeyStatus.key == LEFTKEY) {
m_LEDStatus.frequency -= 10;
if (m_LEDStatus.frequency <= 0)
m_LEDStatus.frequency = 0;
}
else if (m_KeyStatus.key == RIGHTKEY) {
m_LEDStatus.frequency += 10;
if (m_LEDStatus.frequency >= 500)
m_LEDStatus.frequency = 500;
}
}
}
void CLEDTestDlg: etectKeyPress() //模仿键盘处理过程
{
switch (m_KeyStatus.keyState) {
case 0:
if (m_KeyStatus.pressedKey != NOKEY)
m_KeyStatus.keyState++; //去抖动
break;
case 1:
if (m_KeyStatus.pressedKey == NOKEY)
m_KeyStatus.keyState--;
else {
m_KeyStatus.key = m_KeyStatus.pressedKey;
m_KeyStatus.keyEventHandled = false;
m_KeyStatus.keyTimer = 100; //2 seconds
m_KeyStatus.keyState++;
}
break;
case 2:
if (m_KeyStatus.key != m_KeyStatus.pressedKey) {
m_KeyStatus.keyState = 0;
m_KeyStatus.key = NOKEY;
}
else {
if (--m_KeyStatus.keyTimer == 0) {
m_KeyStatus.keyTimer = 50; // 1 second
m_KeyStatus.keyEventHandled = false;
}
}
break;
default:
m_KeyStatus.keyState = 0;
}
}
//处理鼠标左右键的按下
BOOL CLEDTestDlg: reTranslateMessage(MSG* pMsg)
{
switch (pMsg->message) {
case WM_LBUTTONDOWN:
m_KeyStatus.pressedKey = LEFTKEY;
break;
case WM_RBUTTONDOWN:
m_KeyStatus.pressedKey = RIGHTKEY;
break;
case WM_LBUTTONUP:
case WM_RBUTTONUP:
m_KeyStatus.pressedKey = NOKEY;
break;
}
return CDialog:reTranslateMessage(pMsg);
}
欢迎讨论。
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